In the given figure, `a=15m//s^(2)` represents the total acceleration of a particle moving in the clockwise direction in a circle of radius `R=2.5m` at a given instant of time. The speed of the particle is.

Options

A. 4.5 m/s
B. 5.0 m/s
C. 5.7 m/s
D. 6.2 m/s

Answer

c

Explanation

Centripetal accleration of particle moving on a circular path is given by `a_(c)=(v^2))`
In the given figure
`a_(c)=a cos30^(@)=15cos30^(@0m//s^(2)`
implies(v^(2)/®=15cos30^(@)`
impliesv^(2)=Rxx15xx(sqrt(3))/(2)`
`=25xx15xx(sqrt(3))/(2)`
`:.v=5.7m//s`