Two stone of masses `m and 2 m` are whirled in horizontal circles, the heavier one in a radius `r//2` and the lighter one in radius `r`. The tangential speed of lighter stone is `n` times that of the value of heavier stone when the experience same centripetal forces. the value of `n` is

Options

A. 2
B. 3
C. 4
D. 1

Answer

a

Explanation

Given, that two stones of masses m and 2 are whirled in horizontal circle, the heavier one ina radius `(r )/(2)` and lighter one in radius r as shown in figure

As, lighter stones is n times that the value of heavier stone when they experience same centripetal forces , we get
`(F_(c))_("heaiver")=(F_(c))_("lighter")`
`implies(2m(v)^(2))/((r//2))=(m(nv)^(2))/(I)`
`impliesn^(2)=4impliesn=2`