a projectile is fired from the surface of the earth with a velocity of `5ms^(-1)` and angle `theta` with the horizontal. Another projectile fired from another planet with a velocity of `3ms^(-1)` at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth.The value of the acceleration due to gravity on the planet is in `ms^(-2)` is given `(g=9.8 ms^(-2))`

Options

A. 3.5
B. 5.9
C. 16.3
D. 110.8

Answer

a

Explanation

The trajectory of a pirjectile prijected at some angle `theta` with the horizontal direction from ground is given by
`y=xtantheta-(gx^(2))/(2u^(2)cos^(2)theta)
`for equal tarjectories for same angle of projection
`(g)/(u^(2))("constant")implies(9.8)/(5^(2))=(g)/(3^(2))`
`g'=(9.8xx9)/(25)=3.5ms^(-2)`