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A capacity of capacity C(1) is charged u...

A capacity of capacity `C_(1)` is charged up to `V` volt and then connected to an uncharged capacitor of capacity `C_(2)`. Then final potential difference across each will be

A

`(C_(2)V)/(C_(1)+C_(2))`

B

`(C_(1)V)/(C_(1)+C_(2))`

C

`(1+(C_(2))/(C_(1)))V`

D

`(1-(C_(2))/(C_(1)))V`

Text Solution

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The correct Answer is:
B
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