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The magnetic field bar(dB) due to a smal...

The magnetic field `bar(dB)` due to a small current element `bar(dl)` at a distance `vec(r)` and carrying current `'I'` is

A

`dB=(mu_(0))/(4pi)i((dlxxr)/(r))`

B

`dB=(mu_(0))/(4pi)i^(2)((dlxxr)/(r^(2)))`

C

`dB=(mu_(0))/(4pi)i^(2)((dlxxr)/(r))`

D

`dB=(mu_(0))/(4pi)i((dlxxr)/(r^(3)))`

Text Solution

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The correct Answer is:
d
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