`mu` observed `= Sigma mu_(i)X_(i)`
where `mu_(i)` is the dipole moment of the stable conformer and `X_(i)` is the mole fraction of that conformer.

It is given that for conformational isomers, the net dipole moment mu_(obs)=sum mu_(i)x_(i) Where mu_(obs) = obsereved dipole moment of the compound mu_(i) = dipole moment of the stable conformational isomers X_(1) = mole fraction of stable conformers of the compound Z-CH_(2)-CH_(2)-Z draw the Newman projection formula of all stable conformational isomers, if mu_(obs) = 1D, " and " X_(anti) = 0.82, " find " mu_(gauche) . Now draw the Newman projection formula of the most stable conformation of meso Y-CHD-CHD-Y. (a) If Y is CH_(3) ("rotation about "C_(2)-C_(3) " bond") (b) If Y is OH ("rotation about "C_(1)-C_(2) " bond")

Conformation - I

which of the following compound has zero dipole moment in one of the stable conformations?

If mu is the mean of a distribution , then sumf_i(y_i-mu) is equal to

Consider the following conformations of 3-Aminopropanal, amongst the given conformations (P, Q, R, S) one of them is most stable. The correct statements for the above is/are : (I) H-bonding is present in the most stable conformer (II) Gauche conformation is the most stable conformer (III) Anti conformation is the most stable conformer (IV) larger groups being separated by maximum distance in the conformer

Consider the following conformations of 3-Aminopropanal, amongst the given conformations (P, Q, R, S) one of them is most stable. The correct statements for the above is/are (I) H-bonding is present in the most stable conformer (II) Gauche conformation is the most stable conformer (III) Anti conformation is the most stable conformer (IV) larger groups being separated by maximum distance in the conformer