. For `x in R^+, if x, [x], {x}` are in harmonic progression then the value of x can not be equal to (where [*] denotes greatest integer function, {*} denotes fractional part function)

Solve : 4{x}= x+ [x] (where [*] denotes the greatest integer function and {*} denotes the fractional part function.

Solve : 4{x}= x+ [x] (where [*] denotes the greatest integer function and {*} denotes the fractional part function.

Solve : 4{x}= x+ [x] (where [*] denotes the greatest integer function and {*} denotes the fractional part function.

Solve : 4{x}= x+ [x] (where [*] denotes the greatest integer function and {*} denotes the fractional part function.

Consider the function f(x) = {x+2} [cos 2x] (where [.] denotes greatest integer function & {.} denotes fractional part function.)

The number of values of x such that x, [x] and {x} are in arithmetic progression is equal to (where [.] denotes the greatest integer function and {.} denotes the fractional part function)

The number of values of x such that x, [x] and {x} are in arithmetic progression is equal to (where [.] denotes the greatest integer function and {.} denotes the fractional pat function)

The sum of solutions of the equation 2[x] + x =6{x} is (where [.] denotes the greatest integer function and {.} denotes fractional part function)

Solve 1/[x]+1/([2x])= {x}+1/3 where [.] denotes the greatest integers function and{.} denotes fractional part function.