[" 30.Find "lim_(theta rarr(pi)/(4))(1-tan theta)/(1-sqrt(2)sin theta)],[" (年) "(1)/(4)]

lim_(theta rarr(pi)/(2))(sec theta-tan theta)/(pi-2 theta)

lim_(theta rarr(pi)/(6))(4cos^(2)theta-3)/(2sin theta-1)

lim_(theta rarr pi/2)(sec theta-tan theta)/(pi-2 theta)

lim_(theta rarr(pi)/(6))((sin(theta-(pi)/(6)))/(sqrt(3)-2cos theta)

lim_(x rarr(pi)/(2))(1-sin theta)/(((pi)/(2)-theta)cos theta)=

Evaluate : underset ( theta rarr pi //4) ( "lim") ((1- tan theta))/( (1- sqrt(2) sin theta ))

lim_(theta rarr pi/2) (1-sin theta )/((pi/2 - theta) cos theta)=

Let l=lim_(theta rarr0)(sin^(3)theta -tan^(3)theta)/(theta^(5)) and m=lim_(theta rarr(pi)/(4))(((sin theta+cos theta)^(3)-2sqrt(2))/(1-sin2 theta)) .Find the value of [l^(2)+m^(2)] (where [x] denotes largest integer less than or equal to

Evaluate lim_(theta rarr 0) (1-cos 4theta)/(1-cos 5theta)

If m=(lim_(theta rarr(pi)/(4))(((sin theta+cos theta)^(3)-2sqrt(2))/(1-sin2 theta))) then the value of m is