In `Delta A B C` if `a=(b-c) sec theta` then `(2sqrtb c)/(b-c) sin (A/2)=`

In Delta ABC if a=(b-c)sec theta then (2sqrt(bc))/(b-c)sin((A)/(2))=

In DeltaABC if a=(b-c)Sec theta then (2sqrt(bc))/(b-c)"Sin"(A)/(2)=

If a=(b-c)Sec theta , Prove that tan theta=(2sqrt(bc))/(b-c)Sin(A)/(2)

If a = (b-c) "sec" theta , then prove that tan theta = (2sqrt(bc))/(b-c) sin A/2 .

In a Delta ABC " if " a^(2) sin (B - C) + b^(2) sin (C - A) + c^(2) sin (A - B) = 0 , then triangle is

In Delta ABC, if a/c=(sin(A-B))/(sin (B-C)) , then a^2,b^2,c^2 are in

In a Delta ABC, prove that (a sin(B - C))/(b^(2) - c^(2)) = (b sin (C - A))/(c^(2) - a^(2)) = (c sin (A - B))/(a^(2) - b^(2))

If the three side of a triangle be a, b, c and tan theta=(2 sqrt(ab))/(a-b) "sin"(C)/(2) , then show that "sec" theta =(c)/(a-b) .