A certain reaction is at equilbrium at `82^(@)C and Delta H` for this reaction is 21.3 kJ. What would be the value of `Delta S` (in `JK^(-1)mol^(1)`) for the reaction?

Certain reaction is at equilibrium at 82^(@)C and Delta H for this reaction is 21.3 kJ mol^(-1) . What would be the value of Delta S(in JK^(-1) mol^(-1)) for the reaction.

A certain reaction is at equilibrium at 82^(@)C and the enthalpy change for the reaction is 21.3 kJ. The value of Delta S (in JK mol^(-1) for the reaction is

A reaction is at equilibrium at 100^(@)C and the enthalpy change for the reaction is "42.6 kJ mol"^(-1) . What will be the value of DeltaS in "J K"^(-1)"mol"^(-1) ?

A reaction is at equilibrium at 100^(@)C and the enthalpy change for the reaction is "42.6 kJ mol"^(-1) . What will be the value of DeltaS in "J K"^(-1)"mol"^(-1) ?

If for a certain reaction triangle_rH is 30KJ mol^(-1) at 450K, the value of triangle_rS (in JK^(-1)mol^(-1)) for which the same reaction will be spontaneous at the same temperature is

If for a certain reaction triangle_rH is 30KJ mol^(-1) at 450K, the value of triangle_rS (in JK^(-1)mol^(-1)) for which the same reaction will be spontaneous at the same temperature is

The temperature of K at which Delta G =0 for a given reaction with Delta H= -20.5 kJ mol^(-1) and Delta S =- 50.0 JK^(-1)mol^(-1)