If x = `3 + 2sqrt2` find `sqrtx + 1/sqrtx`

If x = 3 + 2 sqrt2 , find the value sqrtx - (1)/(sqrtx)

If x + 7 + 4 sqrt3 , then sqrtx + (1)/(sqrtx) = 4

If x=(3+2sqrt2) then (sqrtx-1/sqrtx)=

If x=3+2sqrt2 find the value of sqrtx-1/sqrtx

If x=5+2sqrt6 then sqrtx+1/sqrtx=

If x = 1 + sqrt2 , then find the value of sqrtx+(1/sqrtx) . यदि x = 1 + sqrt2 , है, तो sqrtx+(1/sqrtx) का मान ज्ञात कीजिए ?

Intergrate the following with respect to x (i) 3sqrt(x^5) (ii) sqrtx - (1)/(sqrtx) (iii) (sqrtx + (1)/(x) )^2