Home
Class 11
MATHS
The number of N=6-(6(log)(10)2+(log)(10)...

The number of `N=6-(6(log)_(10)2+(log)_(10)31)` lies between two successive integers whose sum is equal to (a)5 (b) 7 (c) 9 (c) 10

Promotional Banner

Similar Questions

Explore conceptually related problems

The number N = 6 log_(10) 2+ log_(10) 31 lies between two successive integers whose sum is equal to

The number N = 6 log_(10) 2+ log_(10) 31 lies between two successive integers whose sum is equal to

The number N = 6 log_(10) 2+ log_(10) 31 lies between two successive integers whose sum is equal to

The number N = 6 log_(10) 2+ log_(10) 31 lies between two successive integers whose sum is equal to

The number N=6^(log_(10)40). 5^(log_(10)36) is a natural number ,Then sum of digits of N is :

The number N=6^(log_(10)40)*5^(log_(10)36) is a natural number,Then sum of digits of N is :

The value of (6log_(10)1000)/(3log_(10)100) is equal to a.0 b.1 c.2 d.3