A particle starts from rest in circular path of radius R = 2 m such that its angular velocity is `omega = (pi t)/(3)` rad/s. Find the magnitude of average velocity of particle when it has maoved by angle `60^(@)` from its initial position.

Options

A. `sqrt3 m//s`
B. `2 sqrt3 m//s`
C. `2 sqrt2 m//s`
D. `sqrt2 m//s`

Answer

D

Explanation

As we know
`omegta = (pi t)/(3) `
`alpha = ( d omega)/(dt) = (pi)/(3) rad //s^(2) `
`theta = (pi)/(3) =1/2 alpha t^(2)`
`pi/3 =1/2 (pi//3) t^(2) `
`t = sqrt2s`
Now displacement of paraticle is given as
`d= R =2m`
`V = (2)/(sqrt2) = 2sqrtm//s`