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An acid catalysed hydrolysis of ester fo...

An acid catalysed hydrolysis of ester follows rate law,`R=k[CH_3COOC_2H_5][H^+]`.Half life in presence of 0.1M HA (`ka=10^(-5)`​) is 100 min. Then half life (in min) in presence of 0.01M HCl.

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The correct Answer is:
A
`k^(-1)=k[H^+]`
`H^+=sqrt(0.1xx10^(-5))=10^(-3)`
`100="In2"/(kxx10^(-3))`
`t_(1//2)="In2"/(kxx10^(-2))`=10 min
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