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The equilibrium constant for the esterif...

The equilibrium constant for the esterification reaction of acetic acid and ethyl alcohol at `100^(@)C` is 4. What percentage of alcohol has been esterified ?

A

`45%`

B

`20%`

C

`54%`

D

`66%`

Text Solution

Verified by Experts

The correct Answer is:
D
`{:(,C_(2)H_(5)OH,+,CH_(3)COOH,hArr,CH_(3)COOC_(2)H_(5),+,H_(2)O),(t=0,1,,1,,0,,0),(t=t_(eq),1-x,,1-x,,x,,x):}`
`K=((x)/(v).(x)/(v))/(((1-x))/(V)((1-x))/(V))=(x^(2))/((1-x)^(2))=4`
taking squire root `=(x)/(1-x)=2`
`x=2-2x`
`3x=2`
`x=(2)/(3)`
`rArr alpha = (x)/(a)=(2)/(3xx1)=0.66 rArr 66%`
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