A particle is projected form a horizontal plane `(x-z` plane) such that its velocity vector at time `t` is gives by `vecV = ahati +(b - ct)hatj`. Its range on the horizontal plane is given by

Options

A. `(ba)/c`
B. `(2ba)/c`
C. `(3ba)/c`
D. None

Answer

B

Explanation

`vecV = ahati + (b-"ct")hatj = 4xhati + (U_(y)-"gt")hatj`
`R = (2u_(x) U_(y))/g = (2ab)/c`
`v^(2) = 2g sin theta xx l`
`v^(2)/n^(2) = 2(g sin theta - mu g cos theta)l`
`sin theta(1-1/(1/n^(2))) = mu cos theta`
`mu = tan theta (1- 1/n^(2))`