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A thin circular wire carrying a current ...

A thin circular wire carrying a current `I` has a magnetic moment `M`. The shape of the wire is changed to a square and it carries the same current. It will have a magnetic moment

A

`(pi M)/4`

B

`M/2`

C

`(3M)/4`

D

`pi M`

Text Solution

Verified by Experts

The correct Answer is:
A
`M=iA = ipir^(2)`
`M' = ia^(2), 2pir = 4a`
`=i((pi r)/2)^(2)`
`=pi/4` M
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