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Maximum length of chord of the ellipse x...

Maximum length of chord of the ellipse `x^(2)/8 + y^(2)/4=1`, such that eccentric angles of its extremities differ by `pi/2` is:

Text Solution

Verified by Experts

The correct Answer is:
`4.00`
Let `P=(2sqrt(2) cos theta. 2 tantheta)` and `Q(2sqrt(2) cos(pi/2 + theta) . 2tan(pi/2 + theta))`
or `Q(-2sqrt(2) tantheta. 2 costheta)`
`(PQ)^(2) = 12 + 4 sin 2theta`
`(PQ)_("max") =4`
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