A projectile is fired with velocity u making an angle θ with the horizontal. What is the angular momentum of the projectile at the highest point about the starting point ? (Given the mass of the projectile is m )

Options

A. `(m cos theta)/(2g)`
B. `(m u^(2)sin^(2)theta cos theta)/(2g)`
C. `(m u^(3)cos^(2)theta)/(2g)`
D. `(m u^(3)sin^(@)theta costheta)/(2g)`

Answer

D

Explanation

`"h = maximum height "=(u^(2)sin^(2)theta)/(2g)`
`"Linear momentum "=m u cos theta " at the highest"`
`"point Angular momentum of the projectile at "`
`"the highest point"="linear momentum"xx"perpendicular distance"`
`=m u cos theta xx "h mu cos "theta=(u^(2)sin^(2)theta)/(2g)`
`=(m u^(2)sin^(2)theta cos theta)/(2g)`