The magnetic field in the plane electromagnetic wave is given by
`B_(z)=2xx10^(-7) sin(0.5xx10^(3)x+1.5xx10^(11)t)` tesla.
The expression for electric field will be:

Options

A. `E_(y)=2xx10^(-7)sin(0.5xx10^(3)z+1.5xx10^(11)t)V//m`
B. `E_(x)=2xx10^(-7)sin(0.5xx10^(3)z+1.5xx10^(11)t)V//m`
C. `E_(y)=60 sin(0.5xx10^(3)z+1.5xx10^(11)t)V//m`
D. `E_(x)=60sin(0.5xx10^(3)z+1.5xx10^(11)t)V//m`

Answer

D

Explanation

The electric vector is perpendicular to B as well as direction of propagation of electromagnetic wave.
Therefore, Ex has to be taken.
Further,`" "E_(0)=B_(0)xxc`
`"or "=2 xx10^(-7)xx3xx10^(8)V//M`
`"or "E_(0)=2xx10^(-7)xx3xx10^(8)=60V//M`
`therefore" The corresponding value of the electric field is, "`
`E_(x)=60sin (0.5xx10^(3)z+1.5x10^(11)t)V//M`