For the reaction: X(2)O(4)(l)rarr2XO(2...

For the reaction:
`X_(2)O_(4)(l)rarr2XO_(2)(g)`
`DeltaU=2.1 cal , DeltaS =20 "cal" K^(-1) "at" 300 K`
Hence `DeltaG` is

A

2.7 kcal

B

`-3.3` kcal

C

9.3 kcal

D

None of these

Verified by Experts

`DeltaH=DeltaU=Deltan_(g)RT`
`("2.1 Kcal")+1xx(2)/(1000)xx300`
`="2.7 Kcal"`
`DeltaG=DeltaH-TDeltaS`
`="2.7 Kcal"-300 xx((20)/(1000))`
`=-"3.3 Kcal"`

Similar Questions

Explore conceptually related problems

For the reaction, X_(2)O_(4)(I) rightarrow 2XO_(2)(g) Delta cup = 2.1 k cal, Delta S = 20 cal K^(-1) at 300 K hence, DeltaG is

For the reaction, X_(2)O_(4)(l)rarr2XO_(2)(g),DeltaE=2.1Kcal , DeltaS=20cal//K at 300K . Hence DeltaG is

For the reaction at 25^(@)C, C_(2)O_(4)(l) rarr 2XO_(2)(g) Delta H =2.1 kcal and DeltaS=20 cal K^(-1) . The reaction would be :

For the reaction :- N_(2)O_(4(g))hArr2NO_(2(g)) DeltaU2.0Kcal,DeltaS=50CalK^(-1)at300K calculate DeltaG ?