In an EM wave propagating along X-direction magnetic field scillates at a frequency of `3 × 10^(10) Hz` along Y-direction and has an amplitude of `10^( –7) T`. The expression for electric field will be :-

Options

A. `E_(z) = 30 sin 2 Pi (100_(x) - 3 xx 10^(10)t) V//m`
B. `E_(z) = 300 sin 2 Pi (100_(x) - 3 xx 10^(10)t) V//m`
C. `E_(y) = 30 sin 2 Pi (100_(x) - 3 xx 10^(10)t) V//m`
D. `E_(y) = 300 sin 2 Pi (100_(x) - 3 xx 10^(10)t) V//m`

Answer

A

Explanation

`f = 3 xx 10^(10) H_(2) B_(0) = 10^(-7) T`
`E_(0) = CB_(0) = 3 xx 10^(8) xx 10^(-7) = 30 V//m`
`lambda = C/f = 10^(-2),`
`E_(z) = E_(0) sin (Kx - wt)`
`= 30 sin ((2pi)/(lambda) x - (2 pi)/(T)t)`
`E_(z) = 30 sin 2 pi (100x - 3 xx 10^(10)t)`.