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In an EM wave propagating along X-direct...

In an EM wave propagating along X-direction magnetic field scillates at a frequency of `3 × 10^(10) Hz` along Y-direction and has an amplitude of `10^( –7) T`. The expression for electric field will be :-

A

`E_(z) = 30 sin 2 Pi (100_(x) - 3 xx 10^(10)t) V//m`

B

`E_(z) = 300 sin 2 Pi (100_(x) - 3 xx 10^(10)t) V//m`

C

`E_(y) = 30 sin 2 Pi (100_(x) - 3 xx 10^(10)t) V//m`

D

`E_(y) = 300 sin 2 Pi (100_(x) - 3 xx 10^(10)t) V//m`

Text Solution

Verified by Experts

The correct Answer is:
A
`f = 3 xx 10^(10) H_(2) B_(0) = 10^(-7) T`
`E_(0) = CB_(0) = 3 xx 10^(8) xx 10^(-7) = 30 V//m`
`lambda = C/f = 10^(-2),`
`E_(z) = E_(0) sin (Kx - wt)`
`= 30 sin ((2pi)/(lambda) x - (2 pi)/(T)t)`
`E_(z) = 30 sin 2 pi (100x - 3 xx 10^(10)t)`.
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Knowledge Check

  • In a plane electromagnetic wave propagating in + ve y direction, the electric field oscillates sinusoidally at a frequency 2xx10^(10) Hz and amplitude 48 V/m. The amplitude of oscillating magnetic field will be:

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