A straight conducting wire MN of length 4m is rotated in a uniform magnetic field `vec(b)= 0.1` Tesla (`hat(k)`) about point O with angular speed `omega = 10 rad//s` as shown in the figure. The axis of rotation is parallel to `vec(B)`. Find the potential difference (in volt) between point M and point N.

Answer

`4.80`

Explanation

`e_(1) = (B omega l^(2))/(2) , e_(2) = (B omega l_(2)^(2))/(2)`
`implies V_(N) - V_(M) = e_(2) - e_(1) = (B omega)/(2) (l_(2)^(2) - l_(1)^(2))`
`=2 B omega R^(2) cos theta = 4.8 "volt"`.