A uniform rod of mass m and length `l` can rotate freely on a smooth horizontal plane about a vertical axis hinged at point H. A point mass having same mass m coming with an initial speed u perpendicular to the rod, strikes the rod and sticks to it at a distance of `(3l)/4` from hinge point. Theangular velocity of the rod just after collision is `(36u)/(nl)`. Find the value of n.

Answer

`43.00`

Explanation

Angular Momentum about hinge
`L_(i) = L_(f)`
`"mu" ((3l)/(4)) = ((ml^2)/(3) + m((3l)/(4))^(2)) omega`
`omega = (36 u)/(43 l)`.