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Let sum of ten numbers a, ar, ar^(2) , ....

Let sum of ten numbers `a, ar, ar^(2) , ... Ar^(9)` is 18 and sum of their reciprocal is 6 then product of these ten numbers is.

A

324

B

343

C

243

D

724

Text Solution

Verified by Experts

The correct Answer is:
C
`(a(1+r+r^(2)+........+r^(9)))/(1/a+1/(ar)+......+1/(ar^9))=a^(2)r^(9)=3`
Hence
`(a)(ar)(ar^2).....(ar^9) = (a^2r^9)^(5)`
`=(3)^(5) = 243`.
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