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Surface tension of soap solution is 2xx1...

Surface tension of soap solution is `2xx10^(-2)N//m`. The work done in producing a soap bubble of radius 2 cm is :-

A

`64 Pi xx 10^(-6)J`

B

`32 Pi xx 10^(-6)J`

C

`16 Pi xx 10^(-6)J`

D

`8 Pi xx 10^(-6)J`

Text Solution

Verified by Experts

The correct Answer is:
A
`W = 8 pi R^(2) T = 8 xx pi xx (2 xx 10^(-2))^(2) xx 2 xx 10^(-2)`
`= 64 Pi xx 10^(-6)J`.
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Knowledge Check

  • Surface tension of soap solution is 2 xx 10^(-2) N//m . The work done in producing a soap bubble of radius 2 cm is

    A
    `64pi xx 10^(-6) J`
    B
    `32pi xx 10^(-6) J`
    C
    `16 pi xx 10^(-6) J`
    D
    `8 pi xx 10^(-6) J`

  • The surface tension of a soap solution is 2.1xx10^(-2) N//m . The work done in blowing a soap bubble of diameter 6.0 cm is

    A
    `47.4xx10^(-5)` J
    B
    `11.9xx10^(-5)` J
    C
    `25.4xx10^(-5)` J
    D
    `35.8xx10^(-5)` J

  • The surface tension of soap solution is 10 xx 10^(-2) n/m . The amount of work done in blowing a soap bubble of radius 2 cm is

    A
    `10.04 xx 10^(-4)`J
    B
    `10.4 xx 10^(-5)`J
    C
    `10.04 xx 10^(-3)`J
    D
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