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How many moles of P(4) can be produced b...

How many moles of `P_(4)` can be produced by reaction of `0.10` moles `Ca_(5)(PO_4)_(3) F, 0.36` moles `SiO_(2)` and 0.90 moles C according to the following reaction?
`4Ca_(5)(PO_4)_(3)F + 18SiO_(2) + 30 C to 3P_(4) + 2CaF_(2) + 18CaSiO_(3)+30CO`.

A

`0.060`

B

`0.030`

C

`0.045`

D

`0.075`

Text Solution

Verified by Experts

The correct Answer is:
A

`SiO_(2)` = Limiting reactant
`18 SiO_(2) overset("give")(rarr) 3P_(4)`
`0.36 mol SiO_(2) to 3/18 xx 0.36 = 0.06 mol P_(4)`.
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