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A certain sample of cuprous sulphide is ...

A certain sample of cuprous sulphide is found to have composition `Cu_(1.8) S`, because of presence of some `Cu_(2+)` ions in the lattice. What is the mole % of `Cu_(2+)` in crystal ?

Text Solution

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The correct Answer is:
`11.11`

by law of conservation of charge
`2 xx x + (1.8 -x) xx 1 = 2`
`2x + 1.8 -x 2`
`x = 2-1.8`
`x = 0.2`
`% Cu^(2+) = (0.2)/(1.8) xx 100= 11.11%`.
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