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If the curve ax^(2) + 3y^(2) = 1 and 2x^...

If the curve `ax^(2) + 3y^(2) = 1 and 2x^2 + 6y^2 = 1` cut each other orthogonally then the value of 2a :

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The correct Answer is:
`3.00`
`ax^(2)+3y^(2)=1 and 2x^(2)+6y^(2) = 1`
cut each other orthogonally
`implies 1/a - 1/2 = 1/3 - 1/6`
`implies 1/a = 1/2 + 1/6`
`implies 1/a = 4/6 = 2/3`
`implies a = 3/2`
`implies 2a = 3`.
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