The average translational kinetic energy...

The average translational kinetic energy of 10 gram `H_(2)` at `27 ^(@)C` is -

37250 J

18750 J

12450 J

3737 J

Text Solution

Verified by Experts

The correct Answer is:

`"Avg. trans KE "=(3)/(2)"nRT"=(3)/(2)xx5xx(25)/(3)xx300J`
`=18750J`

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