A resistance `R_(2)` is connected in parallel with a resistance `R_(1)` what resistance `R_(3)` must be connected in series with the combination of `R_(1) and R_(2)` so that the equivalent resistance is equal to the resistance `R_(1)` -

Options

A. `(R_(1)^(2))/(R_(1)+R_(2))`
B. `((R_(1)+R_(2))^(2))/(R_(1))`
C. `(R_(2)^(2))/(R_(1)+R_(2))`
D. `(R_(1)^(2))/(R_(2))`

Answer

A

Explanation

Accordingly `(R_(1)R_(2))/(R_(1)+R_(2))+R_(3)=R_(1)`