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200 cm^(3) of 0.1 M H(2)SO(4) is mixed w...

`200 cm^(3)` of `0.1 M H_(2)SO_(4)` is mixed with `150 cm^(3)` of 0.2M KOH. Find the value of evolved heat.

A

1.7 KJ

B

2.7KJ

C

9.2KJ

D

3.2KJ

Text Solution

Verified by Experts

The correct Answer is:
A
`H_2SO_4+2NaOH to Na_2SO_4 +2H_2O`
`200 x 0.1 x 2=150 xx 0.2`
=40 m .eq.= 30 m.eq.(L.R)
1000 m . eq `H_2SO_4=57.1`
30 m eq. `H_2SO_4=(57.1xx30)/(1000)=1.7KJ`
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