A projectile is thrown from a point on ground with an initial speed u and at anelevatio `theta` to the horizontal. Find the change in momentum of the particle, when it reaches the top most point of its trajectory.

Options

A. `(mu^(3) sin^(2) theta cos theta )/(2g ) `
B. `(mu^3 cos theta sin theta )/(g ) `
C. `(mu^(3) cos theta sin^(2) theta )/g`
D. `(mu^(3) cos^2 theta sin theta )/(2 g)`

Answer

A

Explanation

Angular momentum at poin P
`L=(mu cos theta )H_("max")`
`= mu cos theta (u^2 sin^2 theta )/(2 g)`
`L=(mu^3 sin^2 theta cos theta )/(2 g)`