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In Young's double-slit experiment d//D =...

In Young's double-slit experiment `d//D = 10^(-4)` (d = distance between slits, D = distance of screen from the slits) At point P on the screen, resulting intensity is equal to the intensity due to the individual slit `I_(0)`. Then, the distance of point P from the central maximum is `(lambda = 6000 Å)`

A

2 mm

B

1 mm

C

0.5 mm

D

4 mm

Text Solution

Verified by Experts

The correct Answer is:
A

`cos (phi/2)=1/2`
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