A neutron breaks into a proton and electorn. Calculate the eenrgy produced in this reaction in `m_(e) = 9 xx 10^(-31) kg, m_(p) = 1.6725 xx 10^(-27) kg, m_(n) = 1.6747 xx 10^(-27) kg, c = 3xx10^(8)m//sec`.

Options

A. 0.73 MeV
B. 1.76 MeV
C. 0.12 MeV
D. 931 MeV

Answer

A

Explanation

`E=Deltamxx C^2`
`=[m_n-(m_p+m_e)]xxC^2`
`=[1.6747xx10^(-27)-(1.6725xx10^(-27)+0.00091xx10^(-27)]xxC^2`
= 0.73 MeV