For intensity I of a light of wavelength...

For intensity `I` of a light of wavelength `5000 Å` the photoelectron saturation current is `0.40 mu A` and stopping potential is `1.36 V` , the work function of metal is

2.47 eV

1.36 eV

1.10 eV

0.43 eV

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Verified by Experts

The correct Answer is:

By using `E=W_0+K_"max"`
`E=12375/5000`=2.475

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