In a common emitter amplifier, using output reisistance of `5000` ohm and input resistance fo `2000`ohm, if the peak value of input signal voltage is `10 m V` and `beta=50`, then the peak value of output voltage is

Options

A. `5xx10^(-6)` volt
B. `2.5xx10^(-4)` volt
C. 1.25 volt
D. 125 volt

Answer

C

Explanation

`A_V=beta(R_L/R_I)=50xx(5000/2000)=125`
`therefore DeltaV_e=AVxxDeltaV_b = 125xx10` mV=1.25 volt