At a pressure of 24 xx 10^(5) dyne cm^(-...

At a pressure of `24 xx 10^(5) dyne cm^(-2)`. The volume of `O_(2)` is `10 litre` and mass is `20 g`. The rms velocity will be

`800 "ms"^(-1)`

`400 "ms"^(-1)`

`600 "ms"^(-1)`

Data is incomplete

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Verified by Experts

The correct Answer is:

`v_"rms"=sqrt((gammarho)/rho)`
put `rho=M/V`
`rho=20/10^4`
`v_"rms" = sqrt16.8xx10^2`

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