A particle of mass `6.4xx10^(-27)` kg and charge `3.2xx10^(-19)C` is situated in a uniform electric field of `1.6xx10^5 Vm^(-1)`. The velocity of the particle at the end of `2xx10^(-2)`m path when it starts from rest is :

Options

A. `2sqrt3xx10^5 ms^(-1)`
B. `8xx10^5 ms^(-1)`
C. `16xx10^5 ms^(-1)`
D. `4sqrt2xx10^5 ms^(-1)`

Answer

D

Explanation

`v=sqrt((2qV)/m)=sqrt((2qE.d)/m)`
`v=usqrt2xx10^5`