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You measure two quantities as A=1.0m+-0....

You measure two quantities as `A=1.0m+-0.2m`,`B=2.0m+-0.2m`. We should report correct value for `sqrt(AB)` as

A

1.4 m `pm` 0.4 m

B

1.41 m `pm` 0.15 m

C

1.4 m `pm` 0.3 m

D

1.4 m `pm` 0.2 m

Text Solution

Verified by Experts

The correct Answer is:
D
Let x=`sqrt(AB)`
then `(Deltax)/x=1/2(DeltaA)/A+1/2(DeltaB)/B`
Here `x=sqrt2`
so `Deltax=sqrt2/2[0.2/1.0+0.2/2.0]=0.2`
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