When photons of energy `hv` fall on an aluminium plate (of work function `E_(0)`), photoelectrons of maximum kinetic energy `K` are ejected . If the frequency of the radiation is doubled , the maximum kinetic energy of the ejected photoelectrons will be

Options

A. K
B. K+hv
C. `K+E_0`
D. 2K

Answer

B

Explanation

Let K and K' be the maximum kinetic energy of photoelectrons for incident light of frequency v and 2v respectively .
According to Einstein's photoelectric equation ,
`K=hv-E_0`….(i)
and `K'=h(2v)-E_0`…(ii)
`=2hv-E_0=hv+hv-E_0`
K'=hv+K [using (i)]