The fringe width in Young's double slit ...

The fringe width in Young's double slit experiment on a screen which is placed at a distance of 1 m from the slits `10^(-3)` m apart when the light used has wavelength `6xx10^(-7)` m is equal to :-

`3xx10^(-10)m`

`3xx10^(-4)m `

`6xx10^(-10)m`

`6xx10^(-4)m`

Text Solution

Verified by Experts

The correct Answer is:

`beta=(lambdaD)/d`
`=6xx10^(-4)`

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