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A cylinder of gas is assumed to contain ...

A cylinder of gas is assumed to contain 11.6 kg of butane `(C_4H_10)`. If a normal family needs 20000kJ of energy per day, then the cylinder will last for : (Given that ΔH for combustion of butane is – 2658kJ)

A

20 days

B

18 days

C

26.6 days

D

32 days

Text Solution

Verified by Experts

The correct Answer is:
C
`DeltaH_"released"=(11.6xx10^3)/58xx2658` kJ
No of day =`(11.6xx10^3xx2658)/(58xx20000)`
=26.58
`approx 26.6`
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