`10 L` of hard water requires `0.28 g` of line `(CaO)` for removing hardness. Calculate the temporary hardness in ppm of `CaCO_(3)`.

10 L of hard water requires 0.28 g of lime (CaO) for removing hardness. Calculate the temporary hardness in ppm of CaCO_(3) .

10 L of hard water required 0.56 g of lime (CaO) for removing hardness. Hence, temporary hardness in ppm (part per million 10^(6) ) of CaCO_(3) is:

10 L of hard water required 0.56 g of lime (CaO) for removing hardness. Hence, temporary hardness in ppm (part per million 10^(6) ) of CaCO_(3) is:

10L of hard water required 5.6g of lime for removing hardness. Hence temperorary hardness in ppm of CaCO_(3) is:

10L of hard water required 5.6g of lime for removing hardness. Hence temperorary hardness in ppm of CaCO_(3) is:

10L of hard water required 5.6g of lime for removing haardness. Hence temporary hardness in ppm of CaCO_3 is :

10L of hard water required 5.6g of lime for removing haardness. Hence temporary hardness in ppm of CaCO_3 is :