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Radioactive material A has decay constan...

Radioactive material `A` has decay constant `8 lamda` and material `B` has decay constant `lamda`. Initial they have same number of nuclei. After what time, the ratio of number of nuclei of material `B` to that `A` will be `(1)/( e)` ?

A

`(1)/(lambda)`

B

`(1)/(7lambda)`

C

`(1)/(8lambda)`

D

`(1)/(9lambda)`

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • Two radioactive materials X_1 and X_2 have decay constants 10 lamda and lamda respectively. If initially they have the same number of nuclei, then the ratio of the number of nuclei of X_1 to that of X_2 will be 1//e after a time.

    A
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    B
    `(1)/(2) lamda`
    C
    `(1)/(4 lamda)`
    D
    `( e)/(lamda)`

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    A
    `1/(10lambda)`
    B
    `1/(11lambda)`
    C
    `11/(10lambda)`
    D
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    B
    `((1)/(11lamda))`
    C
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    D
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