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Consider a vector vecF=4hati-3hatj. Anot...

Consider a vector `vecF=4hati-3hatj`. Another vector that is perpendicular to `vecF` is

A

`4hati+3hatj`

B

`6hati`

C

`7hatk`

D

`3hati-4hatj`

Text Solution

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The correct Answer is:
To find a vector that is perpendicular to the given vector \(\vec{F} = 4\hat{i} - 3\hat{j}\), we can use the property that two vectors are perpendicular if their dot product is zero. ### Step 1: Write the given vector The given vector is: \[ \vec{F} = 4\hat{i} - 3\hat{j} \] ### Step 2: Define a general vector Let’s define a general vector \(\vec{G} = a\hat{i} + b\hat{j}\), where \(a\) and \(b\) are the components of the vector we want to find. ### Step 3: Set up the dot product equation For \(\vec{F}\) and \(\vec{G}\) to be perpendicular, their dot product must equal zero: \[ \vec{F} \cdot \vec{G} = 0 \] Calculating the dot product: \[ (4\hat{i} - 3\hat{j}) \cdot (a\hat{i} + b\hat{j}) = 4a - 3b \] ### Step 4: Set the dot product to zero Setting the dot product equal to zero gives us the equation: \[ 4a - 3b = 0 \] ### Step 5: Solve for one variable in terms of the other From the equation \(4a - 3b = 0\), we can express \(b\) in terms of \(a\): \[ 4a = 3b \implies b = \frac{4}{3}a \] ### Step 6: Choose a value for \(a\) We can choose any non-zero value for \(a\) to find a specific vector. Let’s choose \(a = 3\): \[ b = \frac{4}{3} \cdot 3 = 4 \] ### Step 7: Write the perpendicular vector Substituting the values of \(a\) and \(b\) into \(\vec{G}\): \[ \vec{G} = 3\hat{i} + 4\hat{j} \] ### Conclusion Thus, one vector that is perpendicular to \(\vec{F} = 4\hat{i} - 3\hat{j}\) is: \[ \vec{G} = 3\hat{i} + 4\hat{j} \]
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ERRORLESS -VECTORS-Exercise
  1. If a particle of mass m is moving with constant velocity v parallel to...

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  2. Consider two vectors vecF(1)=2hati+5hatk and vecF(2)=3hatj+4hatk. The ...

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  3. Consider a vector vecF=4hati-3hatj. Another vector that is perpendicul...

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  4. Two vector vecA and vecB are at right angles to each other, when

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  5. If |vecV(1)+vecV(2)|=|vecV(1)-vecV(2)| and V(2) is finite, then

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  6. A force vecF=(5hati+3hatj) Newton is applied over a particle which dis...

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  7. The angle between two vectors -2hati+3hatj+k and hati+2hatj-4hatk is

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  8. The angle between the vectors (hati+hatj) and (hatj+hatk) is

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  9. A particle moves with a velocity 6hati-4hatj+3hatk m//s under the infl...

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  10. If vecP.vecQ=PQ then angle between vecP and vecQ is

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  11. A force vecF=5hati+6hatj+4hatk acting on a body, produces a displaceme...

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  12. The angle between the two vectors vecA=5hati+5hatj and vecB=5hati-5hat...

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  13. The vector vecP=ahati+ahatj+3hatj and vecQ=ahati-2hatj-hatk, are perpe...

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  14. A body, constrained to move in the Y-direction is subjected to a force...

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  15. A particle moves in the x-y plane under the action of a force vecF suc...

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  16. The area of the parallelogram represented by the vectors vecA=2hati+3h...

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  17. A vector vecF(1) is along the positive X-axis. If its vectors product ...

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  18. If for two vectors vecA and vecB, vecA xxvecB=0, the vectors

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  19. The angle between (vecAxxvecB) and (vecBxxvecA) is (in radian)

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  20. What is the angle between (vecP+vecQ) and (vecPxxvecQ)

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