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A vector vecF(1) is along the positive X...

A vector `vecF_(1)` is along the positive `X`-axis. If its vectors product with another vector `vecF_(2)` is zero then `vecF_(2)` could be

A

`4hatj`

B

`-(hati+hatj)`

C

`(hatj+hatk)`

D

`(-4hati)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the conditions under which the vector product (cross product) of two vectors is zero. ### Step-by-Step Solution: 1. **Understanding the Given Vectors**: - We have a vector \( \vec{F_1} \) which is along the positive X-axis. We can represent this vector as: \[ \vec{F_1} = F_1 \hat{i} \] where \( F_1 \) is the magnitude of the vector and \( \hat{i} \) is the unit vector in the X direction. 2. **Condition for Zero Vector Product**: - The vector product (cross product) of two vectors \( \vec{A} \) and \( \vec{B} \) is given by: \[ \vec{A} \times \vec{B} = |\vec{A}| |\vec{B}| \sin \theta \hat{n} \] where \( \theta \) is the angle between the two vectors and \( \hat{n} \) is the unit vector perpendicular to the plane formed by \( \vec{A} \) and \( \vec{B} \). 3. **Setting Up the Equation**: - For the vector product \( \vec{F_1} \times \vec{F_2} \) to be zero, we need: \[ |\vec{F_1}| |\vec{F_2}| \sin \theta = 0 \] This can happen if either: - \( |\vec{F_1}| = 0 \) (which is not the case since \( \vec{F_1} \) is given) - \( |\vec{F_2}| = 0 \) (which means \( \vec{F_2} \) is a zero vector) - \( \sin \theta = 0 \) (which means \( \theta = 0^\circ \) or \( \theta = 180^\circ \)) 4. **Analyzing the Angles**: - If \( \theta = 0^\circ \), it means \( \vec{F_2} \) is in the same direction as \( \vec{F_1} \) (parallel). - If \( \theta = 180^\circ \), it means \( \vec{F_2} \) is in the opposite direction to \( \vec{F_1} \) (antiparallel). 5. **Conclusion**: - Therefore, \( \vec{F_2} \) could either be parallel or antiparallel to \( \vec{F_1} \). This means \( \vec{F_2} \) could be any vector along the X-axis, including: \[ \vec{F_2} = k \hat{i} \quad \text{for any scalar } k \] - Specifically, \( k \) could be positive (for parallel) or negative (for antiparallel). ### Final Answer: Thus, \( \vec{F_2} \) could be any vector along the X-axis, including \( \vec{F_2} = k \hat{i} \) where \( k \) is any real number.
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