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A moves with 65km//h while B is coming b...

A moves with `65km//h` while `B` is coming back of `A` with `80km//h`. The relative velocity of `B` with respect to `A` is

A

`80km//h`

B

`60km//h`

C

`15km//h`

D

`145km//h`

Text Solution

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The correct Answer is:
To find the relative velocity of B with respect to A, we can follow these steps: ### Step 1: Understand the velocities of A and B - A is moving at a speed of 65 km/h. - B is moving towards A (coming back) at a speed of 80 km/h. ### Step 2: Define the direction - Let's assume A is moving in the positive direction (to the right). - Since B is coming back towards A, we can consider B's velocity as negative in this context. ### Step 3: Write the velocities in vector form - Velocity of A, \( V_A = +65 \, \text{km/h} \) - Velocity of B, \( V_B = -80 \, \text{km/h} \) (since it is moving towards A) ### Step 4: Calculate the relative velocity of B with respect to A The formula for relative velocity is: \[ V_{B/A} = V_B - V_A \] Substituting the values: \[ V_{B/A} = (-80) - (65) \] ### Step 5: Perform the calculation \[ V_{B/A} = -80 - 65 = -145 \, \text{km/h} \] ### Step 6: Interpret the result The negative sign indicates that B is moving towards A at a speed of 145 km/h. However, since we are interested in the magnitude of the relative velocity, we can state: \[ \text{Relative velocity of B with respect to A} = 145 \, \text{km/h} \] ### Final Answer The relative velocity of B with respect to A is **145 km/h**. ---
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