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Two constant forces F(1)=2hati-3hatj+3ha...

Two constant forces `F_(1)=2hati-3hatj+3hatk(N)` and `F_(2)=hati+hatj-2hatk(N)` act on a body and displace it from the position `r_(1)=hati+2hatj-2hatk(m)` to the position `r_(2)=7hati+10hatj+5hatk(m)`. What is the work done

A

`9J`

B

`41J`

C

`-3J`

D

None of these

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The correct Answer is:
A
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ERRORLESS -VECTORS-Exercise
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