Two boys are standing at the ends A and B of a ground, where `AB=a`. The boy at B starts running in a direction perpendicular to AB with velocity `v_(1)`. The boy at A starts running simultaneously with velocity v and catches the other boy in a time t, where t is :

Options

A. `a//sqrt(v^(2)+v_(1)^(2))`
B. `sqrt(a^(2)//(v^(2)-v_(1)^(2)))`
C. `a//(v -v_(1))`
D. `a//(v +v_(1))`

Answer

B